Question
An ac source is connected to a capacitor $C$. Due to decrease in its operating frequency :

Answer

$i _{ C }= i _{ D }=\frac{ V _{ O }}{ X _{ C }} \sin \omega t$

$i _{ C }= i _{ D }=\left( V _{ O } \omega C \right) \sin \omega t$

On decreasing frequency $i_C \downarrow$

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