Given is a series $L-C-R$ circuit.
Given,
$V_L=36 \,V \quad \dots(i)$
Given
$\sqrt{V_L^2+V_R^2}=39 \,V \quad \dots(ii)$
$\sqrt{V_C^2+V_R^2}=25 \,V \quad \dots(iii)$
So, from Eqs. $(i)$ and $(ii)$, we get
$V_L^2+V_R^2=(39)^2$
$\Rightarrow \quad V_R^2=(39)^2-(36)^2$
$\quad=(39-36)(39+36)=3(75)$
$\therefore \quad V_R=15 \,V \quad \dots(iv)$
From Eqs. $(iii)$ and $(iv)$, we have
$\quad V_C^2+(15)^2=(25)^2$
$\Rightarrow \quad V_C^2=(25)^2-(15)^2=(25-15)(25+15)$
$\therefore \quad V_C^2=10 \times 40 \Rightarrow V_C=20 V \quad \dots(iv)$
Now using,
$\quad V_{L \cdot C \cdot R}=\sqrt{V_R^2+\left(V_L-V_C\right)^2}$, we have
$V_{L-C \cdot R}=V_{A D} =\sqrt{225+(36-20)^2}$
$=\sqrt{225+256}=\sqrt{481} \,V$
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Statement $-II$ : The light coming from the sky is polarized due to scattering of sun light by particles in the atmosphere. The scattering is largest for blue light.