An $\alpha - $ particle travels in a circular path of radius $0.45\, m$ in a magnetic field $B = 1.2\,Wb/{m^2}$ with a speed of $2.6 \times {10^7}\,m/\sec $. The period of revolution of the $\alpha - $ particle is
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(c) $T = \frac{{2\pi m}}{{qB}} = \frac{{2\pi r}}{v} = \frac{{2 \times 3.14 \times 0.45}}{{2.6 \times {{10}^7}}} = 1.08 \times {10^{ - 7}}\sec $
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