- A$\frac{\text{i}_1+\text{i}_2}{\sqrt{2}}$
- B$\frac{|\text{i}_1+\text{i}_2|}{\sqrt{2}}$
- C$\sqrt{\frac{\text{i}_1^2+\text{i}_2^2}{2}}$
- D$\sqrt{\frac{\text{i}_1^2+\text{i}_2^2}{\sqrt{2}}}$
Explanation:
$\text{i}=\text{i}_1\cos\omega\text{t}+\text{i}_2\sin\omega\text{t}$
$\text{I}_\text{rms}=\frac{\int\limits_0^\text{T}\text{I}^2\text{dt}}{\int\limits_0^\text{T}\text{dt}}$
if $\text{I}=\cos\omega\text{t}$
$\text{I}_\text{rms}^2=\frac{\text{I}_0^2}{2}$
$\text{i}=\text{i}_1\cos\omega\text{t}+\text{i}_2\sin\omega\text{t}$
Than $\text{i}_\text{rms}^2=\frac{\text{i}_1^2}{2}+\frac{\text{i}_2^2}{2}$
$\text{i}_\text{rms}=\sqrt{\frac{\text{i}_1^2+\text{i}_2^2}{2}}$
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