b
(b)
$v=\sqrt{\frac{y}{\rho}}=\sqrt{\frac{7.8 \times 10^{10}}{2600}}=5480 \,ml$
Since rod is clamped at the middle, the middle point is a pressure antinode and free ends are nodes. In the fundamental mode there are no other nodes and antinodes. The length of the rod is therefore half the wavelength.
So, $\lambda=2 I=2 \,m$
Frequency $=\frac{v}{\lambda}=\frac{5480}{2}=2740 \,Hz$