An ammeter gives full scale deflection when current of $1.0\, A$ is passed in it. To convert it into $10\, A$ range ammeter, the ratio of its resistance and the shunt resistance will be
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$S = \frac{{{i_g}G}}{{(i - {i_g})}}$ $ \Rightarrow $ $\frac{G}{S} = \frac{{i - {i_g}}}{{{i_g}}} = \frac{{10 - 1}}{1} = \frac{9}{1}$
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