An ammeter of $5\, ohm$ resistance can read $5 \,mA$. If it is to be used to read $100\, volts$, how much resistance is to be connected in series ............... $\Omega $
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By using $R = \frac{V}{{{I_g}}} - G$ $ \Rightarrow $ $R = \frac{{100}}{{5 \times {{10}^{ - 3}}}} - 5 = 19,995\,\Omega $
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