MCQ
An $AP 5, 12, 19, ...$ has $50$ terms. Its last term is
- A$343$
- B$353$
- ✓$348$
- D$362$
✓
Answer
Correct option: C.
$348$
$\text { Given, first term }(a)=5 \text {, }$
$\text { Common difference } d =12-5=7$
$\therefore 50^{\text {th }} \text { term }= a +( n -1) d$
$=5+(50-1) \times 7$
$=5+49 \times 7$
$=348$
$\text { Common difference } d =12-5=7$
$\therefore 50^{\text {th }} \text { term }= a +( n -1) d$
$=5+(50-1) \times 7$
$=5+49 \times 7$
$=348$
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