An average of 265J of heat is transferred per second by a refrige… - Vidyadip

Question

An average of 265J of heat is transferred per second by a refrigerant at temperatures from$23^{\circ}\text C $ to $27^{\circ}\text C. $ Estimate the average suitable power assuming one ideal reversible cycle and not taking in to account any other losses.

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Answer

Given that :
$\begin{array}{l}T_1=27+273=300 K \\T_2=-23+273=250 K \\Q_2=265 J / s\end{array}$
$\text {We know that}\quad\quad\frac{Q_1}{Q_2}=\frac{T_1}{T_2}$
$\text {or}\quad\quad Q_1=\left(\frac{T_1}{T_2}\right) \times Q_2$
$\begin{aligned}\text {Putting the value}\quad \quad Q_1 & =\frac{300}{250} \times 265 \\& =\frac{6}{5} \times 265 \\& =6 \times 53=318 J / S\end{aligned}$
$\therefore$ Suitable average power
$\begin{array}{l}=Q_1-Q_2 \\=318-265 \\=53 W\end{array}$

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