An electric charge $10^{-8}\ C$ is placed at the point $ (4\,m, 7\,m, 2\,m)$. At the point $(1\,m, 3\,m, 2\,m)$, the electric
Medium
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$V=\frac{K Q}{r}=\frac{9 \times 10^{9} \times 10^{-8}}{\sqrt{(1-4)^{2}+(3-7)^{2}+(2-2)^{2}}}=18 V$
and electric field lines will be in all three direction.
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