In the given circuit, a charge of $+80\, \mu C$ is given to the upper plate of the $4\,\mu F$ capacitor. Then in the steady state, the charge on the upper plate of the $3\,\mu F$ capacitor is.....$\mu C$
Medium
Download our app for free and get started
Equivalent circuit
So change on $5\, \mu \mathrm{F}$ will be $+80\, \mu \mathrm{C}$
$\therefore $ Potential across $5 \mu \mathrm{F}=\frac{\mathrm{q}}{\mathrm{C}}=\frac{80 \times 10^{-6}}{5 \times 10^{-6}}=$$16 \mathrm{\,V}$
$\therefore $ Change on $3\, \mu \mathrm{F}=3 \times 10^{-6} \times 16=48\, \mu \mathrm{C}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Electric potential at any point is $V = - 5x + 3y + \sqrt {15} z$, then the magnitude of the electric field isView Solution
- 2View SolutionThe energy stored in the condenser is
- 3The potential at a point $x$ (measured in $μ\ m$) due to some charges situated on the $ x$-axis is given by $V(x)$ =$\frac{{20}}{{{x^2} - 4}}$ $volt$ The electric field $E$ at $x = 4\ μ m$ is given byView Solution
- 4The work done in carrying a charge of $5\,\mu \,C$ from a point $A$ to a point $B$ in an electric field is $10\,mJ$. The potential difference $({V_B} - {V_A})$ is thenView Solution
- 5A capacitor of capacity ${C_1}$ is charged to the potential of ${V_o}$. On disconnecting with the battery, it is connected with a capacitor of capacity ${C_2}$ as shown in the adjoining figure. The ratio of energies before and after the connection of switch $S$ will beView Solution
- 6A parallel plate capacitor has capacitance $C$ . If charges of the plates are $Q$ and $-3Q$ , find the potential difference between the platesView Solution
- 7Five conducting parallel plates having area $A$ and separation between them $d$, are placed as shown in the figure. Plate number $2$ and $4$ are connected wire and between point $A$ and $B$, a cell of emf $E$ is connected. The charge flown through the cell isView Solution
- 8Two capacitors of capacitance $2C$ and $C$ are joined in parallel and charged to potential $V$. The battery is now removed and the capacitor $C$ is filled with a medium of dielectric constant $K$. The potential difference across each capacitor will beView Solution
- 9The radius of nucleus of silver (atomic number $=$ $47$) is $3.4 \times {10^{ - 14}}\,m$. The electric potential on the surface of nucleus is $(e = 1.6 \times {10^{ - 19}}\,C)$View Solution
- 10View SolutionAdielectric slab is inserted between the plates of an isolated charged capacitor. Which of the following quantities will remain the same?