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Current Electricity — Physics STD 10 — Question

ICSE BoardEnglish MediumSTD 10PhysicsCurrent Electricity5 Marks
Question
An electric kettle has a heating element which is rated at 2 kW when connected to a 250 V electric supply. Calculate the
(a) Current which flows in the element when it is connected to a 250 V supply,
(b) Resistance of the filament,
(c) Heat produced in 1 minute by the element,
(d) Cost of running the kettle for 10 minutes a day for 30 days of the month, at the rate of Rs. 3.00 per unit.
✓

Answer

Given power P = 2k W = 2000 W, Voltage = 250 V
(a) Current $I=\frac{P}{V}=\frac{2000}{250}=8 \mathrm{~A}$
(b) Resistance R = $\frac{\mathrm{V}^2}{\mathrm{R}} \mathrm{t}=\frac{(250)^2}{31.25} \times 60=1.2 \times 10^5$ Joules
(d)Energyconsumedperday=$=P \times t=2 \times\left(\frac{10}{60}\right)=0.33 \mathrm{kWh}$
Energy consumed in 30 days= 0.33 x 30 = 10 kWh
Cost of running it @Rs3 per unit = 10 x 3 =Rs 30

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