MCQ
An electromagnetic wave going through vacuum is described by $E = {E_0}\sin (kx - \omega \,t)$; $B = {B_0}\sin (kx - \omega \,t)$. Which of the following equation is true
  • ${E_0}k = {B_0}\omega $
  • B
    ${E_0}\omega = {B_0}k$
  • C
    ${E_0}{B_0} = \omega k$
  • D
    None of these

Answer

Correct option: A.
${E_0}k = {B_0}\omega $
a
(a) $\frac{{{E_0}}}{{{B_0}}} = C.$ also $k = \frac{{2\pi }}{\lambda }$ and $\omega = 2\pi \nu $
These relation gives ${E_0}K = {B_0}\omega $

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