Question
An electron is accelerated through a potential difference of 100 volts. What is the de-Broglie wavelength associated with it? To which part of the electromagnetic spectrum does this value of wavelength correspond?
✓
Answer
$\lambda = \frac{\text{h}}{\sqrt{2\text{meV}}}\text{ or } \lambda = \frac{12.27}{\sqrt{\text{V}}}\mathring{\text{A}}$
$\lambda =\frac{12.27}{\sqrt{100}}\mathring{\text{A}} = \frac{12.27}{10}\mathring{\text{A}}=1.227\mathring{\text{A}}$
This wavelength corresponds to the X rays.
$\lambda =\frac{12.27}{\sqrt{100}}\mathring{\text{A}} = \frac{12.27}{10}\mathring{\text{A}}=1.227\mathring{\text{A}}$
This wavelength corresponds to the X rays.
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