MCQ
An electron is accelerated through a potential difference of $10,000\; \mathrm{V}$. Its de Broglie wavelength is, (nearly):

$\left(\mathrm{m}_{\mathrm{e}}=9 \times 10^{-31}\;\mathrm{kg}\right)$

  • A
    $12.2 \times 10^{-13} \;\mathrm{m}$
  • $12.2 \times 10^{-12} \;\mathrm{m}$
  • C
    $12.2 \times 10^{-14} \;\mathrm{m}$
  • D
    $12.2\; \mathrm{nm}$

Answer

Correct option: B.
$12.2 \times 10^{-12} \;\mathrm{m}$
b
$\lambda=\sqrt{\frac{150}{V}} \mathring A$

$\lambda=\sqrt{\frac{150}{10^{4}}} \mathring A$$=12.27 \times 10^{-12} \;\mathrm{m}$

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