MCQ
An electron is moving in a circle of radius $2 \,m$ with speed $4 \,m / s$ Find the acceleration of the electron. (in $m / s ^{2}$)
- ✓$8$
- B$4$
- C$16$
- D$10$
$a=\frac{v^{2}}{r}$
$=\frac{(4)^{2}}{2}$
$=8 m / s ^{2}$
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$(1)$ The radial acceleration of the rod's center of mass will be $\frac{3 g }{4}$
$(2)$ The angular acceleration of the rod will be $\frac{2 g }{ L }$
$(3)$ The angular speed of the rod will be $\sqrt{\frac{3 g}{2 L}}$
$(4)$ The normal reaction force from the floor on the rod will be $\frac{ Mg }{16}$