An electron is the ground state of hydrogen atom is revolving in anticlockwise direction in a circular orbit of radius $'r'$. The atom is placed is a unifom magnetic field $B$ in such a way magnetic moment of orbital electron makes an angle $30^o$ with the magnetic field. The torque experienced by orbital electon is
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$\vec{\tau}=\vec{M} \times \vec{B}$
$|\vec{\tau}|=M B \sin \theta$
where $\theta$ is the angle between $\vec{M}$ and $\vec{B} \theta=30^{\circ}$
$\therefore \tau=\left(\frac{e h}{4 \pi m}\right)(B) \sin 30^{\circ}=\frac{e h B}{8 \pi m}$
The direction of $\vec{\tau}$ is perpendicular to both $\vec{M}$ and $\vec{B}$.
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