MCQ
An electron microscope is superior to an optical microscope in
- ✓Having better resolving power
- BBeing easy to handle
- CLow cost
- DQuickness of observation
✓
Answer
Correct option: A.
Having better resolving power
a
( a)In electron microscope, electron beam$(\lambda \approx 1{Å})$ is used so it’s $R.P.$ is approx. $5000$ times more than that of ordinary microscope $(\lambda \approx 5000{Å})$.
( a)In electron microscope, electron beam$(\lambda \approx 1{Å})$ is used so it’s $R.P.$ is approx. $5000$ times more than that of ordinary microscope $(\lambda \approx 5000{Å})$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A particle is dropped vertically from rest from a height. The time taken by it to fall through successive distances of $1\, m$ each will then be
→At what angle should an unpolarised beam be incident on a crystal of $\mu = \sqrt 3$ , so that reflected beam is polarised ..........$^o$
→In the adjoining figure the impedance of the circuit will be.....$ohm$
→The input resistance of a silicon transistor is $100\,\,\Omega$. Base current is changed by $40\,\, \mu A$ which results in a change in collector current by $2\,\, mA.$ This transistor is used as a common emitter amplifier with a load resistance of $4\,\,k\Omega$. The voltage gain of the amplifier is
→Two travelling waves of equal amplitudes and equal frequencies move in opposite directions along a string. They interfere to produce a stationary wave whose equation is given by $y=\left(10 \cos \pi x \sin \frac{2 \pi t}{T}\right)\, cm$
→The amplitude of the particle at $x =\frac{4}{3} \,cm$ will be........ $cm$.
The momentum of a photon with energy $20\, eV$ is
→Solid targets of different elements are bombarded by highly energetic electron beams. The frequency $(f)$ of the characteristic $X-$ rays emitted from different targets varies with atomic number $Z$ as
→In a Young's double slit experiment, the angular width of fringe formed on a distant screen is $0.1$ $radian$ . Find the distance between the two slits, if wavelength of light used is $6000\,\mathop A\limits^o $....$\mu m$
→The dimensional formula for a physical quantity $x$ is $\left[ M ^{-1} L ^{3} T ^{-2}\right]$. The errors in measuring the quantities $M , L$ and $T$ respectively are $2 \%, 3 \%$ and $4 \%$. The maximum percentage of error that occurs in measuring the quantity $x$ is
→The difference in the lengths of a mean solar day and a sidereal day is about........$min$
→