An electron, moving along the x- axis with an initial energy of 100, eV, enters a region of magnetic field vec B = (1.5times10^{-3}T)hat k

Q: An electron, moving along the $x-$ axis with an initial energy of $100\, eV$, enters a region of magnetic field $\vec B = (1.5\times10^{-3}T)\hat k$ at $S$ (See figure). The field extends between $x = 0$ and $x = 2\, cm$. The electron is detected at the point $Q$ on a screen placed $8\, cm$ away from the point $S$. The distance $d$ between $P$ and $Q$ (on the screen) is :......$cm$ (electron's charge $= 1.6\times10^{-19}\, C$, mass of electron $= 9.1\times10^{-31}\, kg$)

c ${\text{R}} = \frac{{{\text{mv}}}}{{{\text{qB}}}}$ $ = \frac{{\sqrt {2{\text{m}}({\text{KE}})} }}{{{\text{qB}}}}$ ${\text{R}} = \frac{{\sqrt {2 \times 9.1 \times {{10}^{ - 31}} \times \left( {100 \times 1.6 \times {{10}^{ - 18}}} \right)} }}{{1.6 \times {{10}^{ - 10}} \times 1.5 \times {{10}^{ - 3}}}}$ ${\text{R}} = 2.248\,{\text{cm}}$ $\sin \theta = \frac{2}{{2.248}};\,\,\,\,\,\tan \,\theta = \frac{{QU}}{{TU}}$ $\frac{2}{{1.026}} = \frac{{QU}}{6}$ $QU = 11.69$ ${\text{PU}} = {\text{R}}(1 - \cos \,\theta )$ $ = 1.22$ ${\text{d}} = {\text{QU}} + {\text{PU}}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

An electron, moving along the $x-$ axis with an initial energy of $100\, eV$, enters a region of magnetic field $\vec B = (1.5\times10^{-3}T)\hat k$ at $S$ (See figure). The field extends between $x = 0$ and $x = 2\, cm$. The electron is detected at the point $Q$ on a screen placed $8\, cm$ away from the point $S$. The distance $d$ between $P$ and $Q$ (on the screen) is :......$cm$ (electron's charge $= 1.6\times10^{-19}\, C$, mass of electron $= 9.1\times10^{-31}\, kg$)

A$1.22$
B$2.25$
C$12.87$
D$11.65$

JEE MAIN 2019, Diffcult

STD 11 Science
NEET
STD 12 - 4. Moving charges and magnetism
Physics

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Download App

Similar Questions

1
Two long, straight wires carry equal currents in opposite directions as shown in figure. The separation between the wires is $5.0 \mathrm{~cm}$. The magnitude of the magnetic field at a point $P$ midway between the wires is __________$\mu \mathrm{T}$ (Given : $\mu_0=4 \pi \times 10^{-7} \mathrm{TmA}^{-1}$ )
View Solution
2
A circular loop of radius $R$ carries a current $I$. Another circular loop of radius $r(< < R) $ carries a current $i$ and is placed at the centre of the larger loop. The planes of the two circles are at right angle to each other. Find the torque acting on the smaller loop.
View Solution
3
A long solenoid has a radius $a$ and number of turns per unit length is $n$. If it carries a current $i$, then the magnetic field on its axis is directly proportional to
View Solution
4
A current flows in a conductor from east to west. The direction of the magnetic field at a points above the conductor is .....
View Solution
5
Magnetic dipole moment of a rectangular loop is
View Solution
6
A particle of mass $M$ and charge $Q$ moving with velocity $\mathop v\limits^ \to $ describes a circular path of radius $R$ when subjected to a uniform transverse magnetic field of induction $B$. The work done by the field when the particle completes one full circle is
View Solution
7
In given diagram, two current carrying circular loop of radius $R$ and $2R$ are arranged in $YZ-$ plane and $XZ-$ plane respectively. Common centre of both are at origin $O$. Then what will be angle of resultant magnetic field from $X-$ axis.
View Solution
8
An electron with energy $0.1\,ke\,V$ moves at right angle to the earth's magnetic field of $1 \times 10^{-4}\,Wbm ^{-2}$. The frequency of revolution of the electron will be. (Take mass of electron $=9.0 \times 10^{-31}\,kg$ )
View Solution
9
A metallic block carrying current $I$ is subjected to a uniform magnetic induction $\overrightarrow B $ as shown in the figure. The moving charges experience a force $\overrightarrow F $ given by ........... which results in the lowering of the potential of the face ........ Assume the speed of the carriers to be $v$
View Solution
10
A current of $200\ \mu \mathrm{A}$ deflects the coil of a moving coil galvanometer through $60^{\circ}$. The current to cause deflection through $\frac{\pi}{10}$ radian is:
View Solution

Download our appand get started for free

Similar Questions

Download our app
and get started for free