An electron moving with a velocity ${\vec V_1} = 2\,\hat i\,\, m/s$ at a point in a magnetic field experiences a force ${\vec F_1} = - 2\hat j\,N$ . If the electron is moving with a velocity ${\vec V_2} = 2\,\hat j \,\,m/s$ at the same point, it experiences a force ${\vec F_2} = + 2\,\hat i\,N$ . The force the electron would experience if it were moving with a velocity ${\vec V_3} = 2\hat k$ $m/s$ at the same point is
A
zero
B$2\hat k\,N$
C$- 2\hat k\,N$
D
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A
zero
a Force acting on the particle $=q \cdot \overrightarrow{V \times B}$ $2 \hat{i} q \times \vec{B}=-2 \hat{j}$
Thus magnetic field $\vec{B}$ is in $+v e z$ direction, $viz$ $\hat{k}$. Hence electric force on the particle is $0$
Thus force on the electron experienced when moving with a velocity of $-2 \hat{k}$ will be $0$
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