MCQ
An electron of mass m when accelerated through a potential difference V has de-Broglie wavelength λ. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be
  • A
    $\lambda \frac{m}{M}$
  • $\lambda \sqrt{\frac{\mathrm{m}}{\mathrm{M}}}$
  • C
    $\lambda \frac{m}{M}$
  • D
    $\lambda \sqrt{\frac{\mathrm{M}}{\mathrm{m}}}$

Answer

Correct option: B.
$\lambda \sqrt{\frac{\mathrm{m}}{\mathrm{M}}}$
(b) $\lambda \sqrt{\frac{\mathrm{m}}{\mathrm{M}}}$

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