An electron with kinetic energy $K _{1}$ enters between parallel plates of a capacitor at an angle $'\alpha'$ with the plates. It leaves the plates at angle $' \beta '$ with kinetic energy $K _{2}$. Then the ratio of kinetic energies $K _{1}: K _{2}$ will be ....... .
  • A$\frac{\sin ^{2} \beta}{\cos ^{2} \alpha}$
  • B$\frac{\cos ^{2} \beta}{\cos ^{2} \alpha}$
  • C$\frac{\cos \beta}{\cos \alpha}$
  • D$\frac{\cos \beta}{\sin \alpha}$
JEE MAIN 2021, Diffcult
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