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Sound Waves — Physics STD 12 Science — Question

Bihar BoardEnglish MediumSTD 12 SciencePhysicsSound Waves2 Marks
Question
An electronically driven loudspeaker is placed near the open end of a resonance column apparatus. The length of air column in the tube is 80cm. The frequency of the loudspeaker can be varied between 20Hz-2kHz. Find the frequencies at which the column will resonate. Speed of sound in air = 320m/s.
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Answer

The resonance column apparatus is equivalent to a closed organ pipe.

Here $\text{l}=80\text{cm}=10\times10^{-2}\text{m};\ \text{v}=320\text{m/s}$

$\Rightarrow\text{n}_0=\frac{\text{v}}{4\text{l}}=\frac{320}{4\times50\times10^{-2}}=100\text{Hz}$

So the frequency of the other harmonics are odd multiple of n0 = (2n + 1)100Hz.

According to the question, the harmonic should be between 20Hz and 2KHz.

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