Question
An element belongs to 5th period and 3rd group, identify the element.

Answer

$Y(39): 1 s^2 ~2 s^2 ~2 p^6 ~3 s^2 ~3 p^6 ~4 s^2 ~3 d^{10} ~4 p^6 \underline{5 s^2} \underline{~4 d^1}$. The element is Ytterium(39).
It belongs to 5th period and 3rd group due to 3 valence electrons.

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