MCQ
An element ' $E$ ' has the ionisation enthalpy value of $374 \mathrm{~kJ} \mathrm{~mol}^{-1}$. 'E' reacts with elements A, B, C and D with electron gain enthalpy values of $-328,-349$, -325 and $-295 \mathrm{~kJ} \mathrm{~mol}^{-1}$, respectively.
The correct order of the products EA, EB, EC and ED in terms of ionic character is :
  • $\mathrm{EB}>\mathrm{EA}>$ EC $>$ ED
  • B
    $\mathrm{ED}>\mathrm{EC}>\mathrm{EA}>\mathrm{EB}$
  • C
    $\mathrm{EA}>$ EB $>$ EC $>$ ED
  • D
    $\mathrm{ED}>\mathrm{EC}>\mathrm{EB}>\mathrm{EA}$

Answer

Correct option: A.
$\mathrm{EB}>\mathrm{EA}>$ EC $>$ ED
(A)
Sol.
Difference between I.E. & E.G.E increases, ionic character increases.

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