MCQ
An element $'P'$ has atomic number $56.$ What will be the formula of its halide ?
- A$PX$
- ✓$PX_2$
- C$PX_3$
- D$P_2X_3$
✓
Answer
Correct option: B.
$PX_2$
b
Element $'P ^{\prime}$ with atomic number $56$ will lose two electrons to form $P ^{2+}$ ion with $54$ electrons corresponding to the stable noble gas electronic configuration. Halogen gains one electron to form $X ^{-}$ion. One $P ^{2+}$ ion combines with two $X ^{-}$ ions to form $PX _2$.
Element $'P ^{\prime}$ with atomic number $56$ will lose two electrons to form $P ^{2+}$ ion with $54$ electrons corresponding to the stable noble gas electronic configuration. Halogen gains one electron to form $X ^{-}$ion. One $P ^{2+}$ ion combines with two $X ^{-}$ ions to form $PX _2$.
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