$t=\frac{A B}{330}+\frac{B C}{330}$
$5=\frac{0.9 \times 1000}{330}+\frac{\mathrm{BC}}{330}$
$\therefore \mathrm{BC}=750 \mathrm{m}$
Distance travelled by engine in $5\, sec$
$=900 \mathrm{m}-750 \mathrm{m}=150 \mathrm{m}$
Therefore velocity of engine
$=\frac{150 \mathrm{m}}{5 \mathrm{sec}}=30 \mathrm{m} / \mathrm{s}$
