A fork of frequency $256\, Hz$ resonates with a closed organ pipe of length $25.4\, cm$. If the length of pipe be increased by $2\, mm$, the number of beats/sec. will be
A$4$
B$1$
C$2$
D$3$
AIIMS 2014, Medium
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C$2$
c $n_{1}=256=\frac{v}{4 \ell_{1}}=\frac{v}{4 \times 25.4}$
No. of $beats/sec$ $=\mathrm{n}_{1}-\mathrm{n}_{2}=256-254=2$
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