An equilibrium mixture of the reaction 2 H_2 S_ (g) 2 H_2 _ (g) +… - Vidyadip

MCQ

An equilibrium mixture of the reaction $2{H_2}S_{(g)}$ $\rightleftharpoons$ $2{H_2}_{(g)} + {S_2}_{(g)}$ had $0.5$ $mole$ ${H_2}S$, $0.10$ $mole$ ${H_2}$ and $0.4$ $mole$ ${S_2}$ in one litre vessel. The value of equilibrium constant $(K)$ in mole litre$^{-1}$ is

A
$0.004$
B
$0.008$
✓
$0.016$
D
$0.16$

✓

Answer

Correct option: C.

$0.016$

(c) $K = \frac{{{{[{H_2}]}^2}[{S_2}]}}{{{{[{H_2}S]}^2}}} = \frac{{{{[0.10]}^2}[0.4]}}{{{{[0.5]}^2}}} = 0.016$

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