Question
An example of a perfect diamagnet is a superconductor. This implies that when a superconductor is put in a magnetic field of intensity $B$, the magnetic field $B_s$ inside the superconductor will be such that
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$\left(\frac{1}{4 \pi \in_0}=9 \times 10^9 \mathrm{SI}\right.$ unit, mass of $\alpha$ particle $=$ $\left.6.72 \times 10^{-27} \mathrm{~kg}\right)$

