MCQ
An ideal gas undergoes cyclic process $\text{ABCDA}$ as shown in given $PV$ diagram. The amount of work done by the gas is:
- A$6\text{P}_0\text{V}_0$
- B$-2\text{P}_0\text{V}_0$
- C$+2\text{P}_0\text{V}_0$
- ✓$+4\text{P}_0\text{V}_0$
✓
Answer
Correct option: D.
$+4\text{P}_0\text{V}_0$
The direction of arrows is anticlockwise so work done is negative equal to the area of loop $=-(3\text{V}_0-\text{V}_0)(2\text{P}_0-\text{P}_0)=-2\text{P}_0\text{V}_0$ verifies the option $(b).$
New work implies external work is done on the system.
New work implies external work is done on the system.
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