MCQ
An infinitely long conductor PQR is bent to form a right angle as shown. A current I flows through PQR The magnetic field due to this current at the point M is $H_1$. Now another infinitely long straight conductor QS is connected at Q so that the current is I/2 in QR as well as in QS, The current in PQ remaining unchanged. The magnetic field at M is now $H_2$. The ratio $H_1/H_2$ is given by


- A$\frac{1}{2}$
- B1
- ✓$\frac{2}{3}$
- D2
