An insulating pipe of cross-section area 'A' contains an electrolyte which has two types of ions rightarrow their charges being -e and +2e. A potential

Q: An insulating pipe of cross-section area $'A'$ contains an electrolyte which has two types of ions $\rightarrow$ their charges being $-e$ and $+2e$. $A$ potential difference applied between the ends of the pipe result in the drifting of the two types of ions, having drift speed $= v$ ($-ve$ ion) and $v/4$ ($+ve$ ion). Both ions have the same number per unit volume $= n$. The current flowing through the pipe is

d We have two types of charges $-e$ and $+ 2 e$ When a potential different is applied both the charges drift in opposite directions. $\therefore \mathrm{i}=\mathrm{neV}_{\mathrm{d} \mathrm{A}}$ $i_{(+v e)}=(n)(2 e) \frac{\left(V_{d}\right)}{4} A=\frac{n e V_{d} A}{2}$ $\mathrm{i}_{(-\mathrm{e})}=\mathrm{n}(-\mathrm{e})\left(-\mathrm{V}_{\mathrm{d}}\right), \mathrm{A}=\mathrm{n}_{\mathrm{e}} \mathrm{V}_{\mathrm{d}} \mathrm{A}$ $i_{total}$ $=i+2 e+i-e$ $i=\frac{3}{2} n e V_{d} A$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

An insulating pipe of cross-section area $'A'$ contains an electrolyte which has two types of ions $\rightarrow$ their charges being $-e$ and $+2e$. $A$ potential difference applied between the ends of the pipe result in the drifting of the two types of ions, having drift speed $= v$ ($-ve$ ion) and $v/4$ ($+ve$ ion). Both ions have the same number per unit volume $= n$. The current flowing through the pipe is

A$nev A/2$
B$nev A/4$
C$5nevA/2$
D$3 nev A/2$

Advanced

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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