MCQ
An object is projected from ground with speed $u$ at angle $\theta$ with horizontal. the radius of curvature of its trajectory at maximum height from ground is ..........
  • A
    $\frac{u^2 \sin 2 \theta}{g}$
  • $\frac{u^2 \cos ^2 \theta}{g}$
  • C
    $\frac{u^2 \sin ^2 \theta}{g}$
  • D
    $\frac{u^2 \sin ^2 \theta}{2 g}$

Answer

Correct option: B.
$\frac{u^2 \cos ^2 \theta}{g}$
b
(b)

$a_c=\frac{v^2}{r}$

$r=\frac{v^2}{a_c}, \frac{u^2 \cos ^2 \theta}{g}$

$r=\frac{u^2 \cos ^2 \theta}{g}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions