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An object of mass $m$ is suspended at the end of a massless wire of length $L$ and area of cross$-$section, $A$. Young modulus of the material of the wire is $Y$. If the mass is pulled down slightly its frequency of oscillation along the vertical direction is
  • A$f =\frac{1}{2 \pi} \sqrt{\frac{ YA }{ mL }}$
  • B$f=\frac{1}{2 \pi} \sqrt{\frac{Y L}{m A}}$
  • C$f=\frac{1}{2 \pi} \sqrt{\frac{m A}{Y L}}$
  • D$f =\frac{1}{2 \pi} \sqrt{\frac{ mL }{ YA }}$
JEE MAIN 2020, Medium
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