An observer is approaching with a speed $v$, towards a stationary source emitting sound waves of wavelength $\lambda_0$. The wavelength shift detected by the observer is (Take $c=$ speed of sound)
A$\frac{\lambda_0 V}{c}$
B$\frac{\lambda_0 c}{v}$
C$\frac{\lambda_0 v^2}{c^2}$
D
Zero
Easy
Download our app for free and get started
D
Zero
d (d)
In Doppler effect only change in frequency is observed and not change in wavelength if observer approaches the source.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A cylindrical tube, open at both ends, has a fundamental frequency ${f_0}$ in air. The tube is dipped vertically into water such that half of its length is inside water. The fundamental frequency of the air column now is
Two sound waves with wavelengths $5.0\,\, m$ and $5 .5\,\, m$ respectively, each propagate in a gas with velocity $330\,\, m/s.$ We expect the following number of beats per second.
A whistle emitting a loud sound of frequency $540 \,Hz$ is whirled in a horizontal circle of radius $2 \,m$ and at a constant angular speed of $15 \,rad / s$. The speed of sound is $330 \,m / s$. The ratio of the highest to the lowest frequency heard by a listener standing at rest at a large distance from the centre of the circle is
If given wave has propagation constant $\frac{5 \pi}{7}\, rad/m$ then phase difference between two particle having distance difference $\frac{49}{22} \,m$ is ..... $rad.$
A string is producing transverse vibration whose equation is $y = 0.021\;\sin (x + 30t)$, Where $x$ and $y$ are in meters and $t$ is in seconds. If the linear density of the string is $1.3 \times {10^{ - 4}}\,kg/m,$ then the tension in the string in $N$ will be