- AListens resonance
- ✓Listens beats
- CWill not listen sound due to destructive interference
- DWill listen intensive sound due to constructive interference
Since, both are sound waves, we have $v_1=v_2=v$
For one wave the traveler is moving towards the source,
$\therefore v^{\prime}=v\left(\frac{v-v_0}{v}\right)$
For the other the traveler is moving away from the source
$\therefore v^{\prime}=v\left(\frac{v+v_0}{v}\right)$
Seeing this, we can conclude that the waves are in phase with each other and are fluctuating repeatedly.
Since, they are sound waves they are periodic in nature. Hence, we got two waves that are periodic and are repeatedly fluctuating. This is the condition of beats. So, beats will be produced and the traveler will listen to beats.
Option $(B)$ is the correct answer.
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$(A)$ the ring has pure rotation about its stationary $CM$.
$(B)$ the ring comes to a complete stop.
$(C)$ friction between the ring and the ground is to the left.
$(D)$ there is no friction between the ring and the ground.