An open tube is in resonance with string (frequency of vibration of tube is $n_0$). If tube is dipped in water so that $75\%$ of length of tube is inside water, then the ratio of the frequency of tube to string now will be
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A transverse wave of amplitude $0.5\, m$ and wavelength $1\, m$ and frequency $2\, Hz$ is propagating in a string in the negative $x-$direction. The expression for this wave is
A source and an observer move away from each other with a velocity of $10\; m/s$ with respect to ground. If the observer finds the frequency of sound coming from the source as $1950 \;Hz$, then actual frequency of the source is .... $Hz$ (velocity of sound in air = $340\; m/s$)
A transverse wave is described by the equation $y = A \,\,sin\,[2\pi (f t - x/\lambda ) ]$.The maximum particle velocity is equal to four times the wave velocity if:
A man can hear sounds in frequency range $120\,Hz$ to $12020\,Hz$. only. He is vibrating a piano string having a tension of $240\,N$ and mass of $3\,gm$ . The string has a length of $8\,m$ . How many different frequencies can he hear ?
Consider two sound sources $S_1$ and $s_2$ having same frequency $100\,\,Hz$ and the observer $O$ located between them as shown in the fig. All the three are moving with same velocity in same direction. The beat frequency of the observer is .... $Hz$
The extension in a string obeying Hooke's law is $x.$ The speed of sound in the stretched string is $v.$ If the extension in the string is increased to $1.5x$, the speed of sound will be
Two waves are represented by the equations : $y_1 = a\, sin\,(\omega t + kx + 0.57)\, m$ and $y_2 = a\, cos\,(\omega t + kx)\, m$, where $x$ is in $metres$ and $t$ is in $seconds$ . The phase difference between them is ..... $radian$
The frequency changes by $10\%$ as a sound source approaches a stationary observer with constant speed $v_s$. What would be the percentage change in frequency as the source recedes the observer with the same speed. ... $\%$ Given that $v_s < v$. ($v =$ speed of sound in air)