MCQ
An optically active compound $X$ has molecular formula $C_4H_8O_3.$ It evolves $CO_2$ with $NaHCO_3.$ $'X' $ Reacts with $LiAlH_4$ to give an achiral compound. $'X'$ is
- A$\begin{array}{*{20}{c}}
{C{H_3} - C{H_2} - CH - COOH}\\
{\,\,\,\,|}\\
{\,\,\,\,\,\,\,OH}
\end{array}$ - B$\begin{array}{*{20}{c}}
{C{H_3} - CH - COOH}\\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{\,\,\,\,\,\,\,\,\,C{H_2} - OH}
\end{array}$ - ✓$\begin{array}{*{20}{c}}
{C{H_3} - CH - COOH}\\
\,\,\,\,{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
\,\,\,\,{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ - D$\begin{array}{*{20}{c}}
{C{H_3} - CH - C{H_2} - COOH}\\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
