An optically active hydrocarbon (X) on catalytic hydrogenation gi… - Vidyadip

MCQ

An optically active hydrocarbon $(X)$ on catalytic hydrogenation gives an optically inactive compound $(Y),$
$\mathrm{C}_6 \mathrm{H}_{14}$. The hydrocarbon $(X)$ is $-$

✓
$3-$ methyl $-1-$ pentene
B
$3-$ methyl $-2-$ pentene
C
$2-$ ethyl $-1-$ butene
D
$3-$ methylcyclopentene

✓

Answer

Correct option: A.

$3-$ methyl $-1-$ pentene

The optically active hydrocarbon $X$ is $3-$ methyl $-1-$ pentene $\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}\left(\mathrm{CH}_3\right) \mathrm{CH}_2 \mathrm{CH}_3$.
On catalytic hydrogenation, it forms, $3-$ methyl pentane $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}\left(\mathrm{CH}_3\right) \mathrm{CH}_2 \mathrm{CH}_3$, which is optically inactive.

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