MCQ
An organic compound containing $C$ and $H$ has $92.3\%$ of carbon, its empirical formula is :
  • $\ce{CH}$
  • B
    $\ce{CH_3}$
  • C
    $\ce{CH_2}$
  • D
    $\ce{CH_4}$

Answer

Correct option: A.
$\ce{CH}$
Element $\%$ $\%$ atomic weight Simplest ratio
$C$ $92.3$ $\frac{92.3}{12}=7.69$ $\frac{7.69}{7.69}=1$
$H$ $7.7$ $\frac{7.7}{1}=7.70$ $\frac{7.70}{7.69}=1$
$\therefore$ Empirical formula $= \ce{CH}$

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