MCQ
An organic compound containing $C$ and $H$ has $92.3\%$ of carbon, its empirical formula is :
- ✓$\ce{CH}$
- B$\ce{CH_3}$
- C$\ce{CH_2}$
- D$\ce{CH_4}$
| Element | $\%$ | $\%$ atomic weight | Simplest ratio |
| $C$ | $92.3$ | $\frac{92.3}{12}=7.69$ | $\frac{7.69}{7.69}=1$ |
| $H$ | $7.7$ | $\frac{7.7}{1}=7.70$ | $\frac{7.70}{7.69}=1$ |
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