MCQ
An organic compound contains $C = 74.0\% ,$ $H = 8.65\% $ and $N = 17.3\% $. Its Empirical formula is
- A${C_5}{H_8}N$
- B${C_{10}}{H_{12}}N$
- ✓${C_5}{H_7}N$
- D${C_{10}}{H_{14}}N$
✓
Answer
Correct option: C.
${C_5}{H_7}N$
c
(b)
(b)
Element No. of Moles Simple Ratio
$C = 74$ |
$74/12 = 6.1$ |
$6.1/1.2 = 5.08$ or $5$ |
$H = 8.65$ |
$8.65/1= 8.65$ |
$8.6/1.2 = 7.16$ or $7$ |
$N = 17.3$ |
$17.3/14 = 1.2$ |
$1.2/1.2 =$ $1$ or $1$ |
Therefore Empirical formula $ = {C_5}{H_7}N$.
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