MCQ
An organic compound has a triple bond and not double bond. It can be tested by
- ABromine water
- BBayer’s reagent
- CFehling solution
- ✓Ammonical silver nitrate
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$C{H_3}CHBrC{H_2}C{H_3}\xrightarrow{{alc.\,KOH}}$
$(i)$ $C{H_3}CH = CHC{H_3}$ (major product)
$(ii)$ $C{H_2} = CHC{H_2}C{H_3}$ (minor product)
$(A)$Covalent radius decreases down the group from $\mathrm{C}$ to $\mathrm{Pb}$ in a regular manner.
$(B)$ Electronegativity decreases from $\mathrm{C}$ to $\mathrm{Pb}$ down the group gradually.
$(C)$ Maximum covalence of $\mathrm{C}$ is $4$ whereas other elements can expand their covalence due to presence of $d$ orbitals.
$(D)$ Heavier elements do not form $\mathrm{p} \pi-p \pi$ bonds.
$(E)$ Carbon can exhibit negative oxidation states.
Choose the correct answer from the options given below: