MCQ
An organic compound has $C = 60\%$, $H = 13.3\%$ and $O = 26.7\%$. Its empirical formula will be
- A${C_3}{H_6}O$
- B${C_2}{H_6}{O_2}$
- C${C_4}{H_8}{O_2}$
- ✓${C_3}{H_8}O$
✓
Answer
Correct option: D.
${C_3}{H_8}O$
d
(d)
(d)
Elements $\%$ No. of moles Simple ratio
|
$C$ |
$60\%$ |
$60/12 = 5 $ |
$3.01$ |
|
$ H$ |
$13.3\%$ |
$13.3/1 = 13.3$ |
$8.01$ |
|
$O$ |
$26.7\%$ |
$26.7/16 = 1.66$ |
$1$ |
Empirical formula =${{C}_{3}}{{H}_{8}}O$ .
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