MCQ
An organic compound is subjected to chlorination to get compound A using $5.0\, \mathrm{~g}$ of chlorine. When $0.5\, \mathrm{~g}$ of compound $\mathrm{A}$ is reacted with $\mathrm{AgNO}_{3}$ [Carius Method], the percentage of chlorine in compound $A$ is $.....$ when it forms $0.3849$ $g$ of $\mathrm{AgCl}$. (Round off to the Nearest Integer)

(Atomic masses of $\mathrm{Ag}$ and $\mathrm{Cl}$ are $107.87$ and $35.5$ respectively)

  • $19$
  • B
    $21$
  • C
    $25$
  • D
    $80$

Answer

Correct option: A.
$19$
a
$\mathrm{n}_{\mathrm{cl}} \text { in compound }=\mathrm{n}_{\mathrm{AgCl}}=\frac{0.3849 \mathrm{~g}}{(107.87+35.5)}\, \mathrm{g} / \mathrm{mol}$

$\Rightarrow \text { mass of chlorine }=\mathrm{n}_{\mathrm{Cl} } \times 35.5=0.0953\, \mathrm{gm}$

$\Rightarrow\, \% \text { wt of chlorine }=\frac{0.0953}{0.5} \times 100$

$\quad=19.06\, \%$

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