Question
An organic compound with the molecular formula C9H10O forms 2,4-DNP derivative, reduces Tollens’ reagent and undergoes Cannizzaro reaction. On vigorous oxidation, it gives 1, 2-benzenedicarboxylic acid. Identify the compound.
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Why do transition elements form coloured compounds explain?
Answer the following :
(a) Sulphurous acid is a reducing agent.
(b) Fluorine forms only one oxoacid.
(c) Boiling point of noble gases increases from He to Rn.
(a) Sulphurous acid is a reducing agent.
(b) Fluorine forms only one oxoacid.
(c) Boiling point of noble gases increases from He to Rn.
(i) Write the equation for the reaction of $CH _3 I$ with $KNO _2$ and $AgNO _2$.
(ii) Write the Friedel-Crafts reaction to prepare toluene from benzene.
→(ii) Write the Friedel-Crafts reaction to prepare toluene from benzene.
The half-life for radioactive decay of $^{14}C$ is 5730 years. An archaeological artifact contained wood that had only 80% of the $^{14}C$ found in a living tree. Estimate the age of the sample.
→Account for the following:
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- Phenol is more easily nitrated than benzene.
Account for the following :
Methyl amine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
Methyl amine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
If $6 \times 10^{20}$ electron are used in reduction of an ion to form an atom, then find the equivalent of the ion.
→State the limitations of Valence bond theory
Write two main functions of carbohydrates in plants.
Calculate the degree of dissociation $(\alpha)$ of acetic acid if its molar conductivity $(\wedge_m)$ is 39.05 S cm2mol–1.
Given $\lambda^0$(H+) = 349.6 S cm2 mol–1
$\lambda^0$(CH3COO–) = 40.9 S cm2 mol–1
→Given $\lambda^0$(H+) = 349.6 S cm2 mol–1
$\lambda^0$(CH3COO–) = 40.9 S cm2 mol–1