Question
An organic compound ‘$X$’ having molecular formula $\ce{C_4H_8O}$ gives orange $-$ red ppt. with $2, 4-\ce{DNP}$ reagent. It does not reduce Tollens’ reagent but gives yellow ppt. of iodoform on heating with $\ce{NaOI}$. Compound $X$ on reduction with $\ce{LiAlH_4}$ gives compound ‘$Y$’ which undergoes dehydration reaction on heating with conc. $\ce{H_2SO_4}$ to form But $-2$-ene. Identify the compounds $X$ and $Y$.

Answer

$X = \ce{CH_{3 }— CO — CH_{2 }— CH_3} /$ Butan $-2-$ one
$Y= \ce{CH_{3 }— CH(OH) — CH_{2 }— CH_3} / $Butan $-2-$ ol

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