An ornament weighs $10\, g$ in air and $6\, g$ in water. Density of material of ornament is $20\,\frac{g}{{cc}}$. The volume of cavity in ornament is ........ $cc$
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Volume of matereal
$\mathrm{V}_{\mathrm{m}}=\frac{\mathrm{m}}{\rho_{\mathrm{m}}}=\frac{10}{20}=0.5 \mathrm{cc}$
$\because F_{\mathrm{T}}=V \cdot \rho g$
$10 \mathrm{g}-6 \mathrm{g}=\mathrm{v} \rho \mathrm{g}$
$4 g=V \rho g$
so volume of body $\mathrm{V}=4 \mathrm{cc}$
volume of cavity $=4-0.5=3.5 \mathrm{cc}$
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