MCQ
An X-ray machine has an accelerating potential difference of 25,000 volts. By calculation the shortest wavelength will be obtained as (h = $6.63 \times 10^{-34} \mathrm{~J}-\mathrm{sec}$; e =$ 1.6.\times 10^{-19} $ coulomb)
  • A
    0.25 Å
  • 0.50 Å
  • C
    1.00 Å
  • D
    2.50 Å

Answer

Correct option: B.
0.50 Å
(b) 0.50 Å

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