Question
Analysis shows that $\ce{FeO}$ has a non$-$stoichiometric composition with formula $Fe_{0.95}O.$ Give reason.

Answer

$\ce{FeO}$ has a non$-$stoichiometric composition with the formula $Fe_{0.95}O,$ because $Fe$ is present in both $+2$ and $+3$ oxidation states.

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